Let A, B, C, D be points on a vertical line such that AB = BC = CD. If a body is released from position A, the times of descent through AB, BC and CD are in the ratio.

A, B, C are points in a vertical line such that AB=BC . If a body falls freely from rest at A, and t_1 and t_2 are times taken to travel distances AB and BC, then ratio (t_2/t_1) is

A, B, C are points in a vertical line such that AB = BC. If a body falls freely from rest at A and t_(1) and t_(2) are times taken to travel distances AB and BC, then ratio (t_(2)//t_(1)) is

A, B, C are points in a vertical line such that AB = BC. If a body falls freely from rest at A and t_(1) and t_(2) are times taken to travel distances AB and BC, then ratio (t_(2)//t_(1)) is

A, B,C and D are points on a line such that point B biscets line AC and point A bisects line CD. What is the ratio of AB to CD ?

In Fig. 2.15, points A,B,C,D and E are collinear such that AB = BC = CD= DE. Then mid point of AE is __________

In Fig. 2.15, points A,B,C,D and E are collinear such that AB = BC = CD= DE. Then mid point of CE is __________

In Fig. 2.15, points A,B,C,D and E are collinear such that AB = BC = CD= DE. Then AE = ________ xx AB.

In Fig. 2.15, points A,B,C,D and E are collinear such that AB = BC = CD= DE. Then AD = AB + ________