A car , starting from rest, accelerates at the rate `f` through a distance `S` then continues at constant speed for time `t` and then decelerates at the rate `(f)/(2)` to come to rest . If the total distance traversed is `15 S` , then

A car, starting from rest, accelerates at the rate f through a distance s, then continues at constant speed for time t and then decelerates at the rate f/ 2 to come to rest. If the total distance travelled is 15 s, then

A car, starting from rest, accelerates at the rate f through a distance s, then continues at constant speed for time t and then decelerates at the rate f/ 2 to come to rest. If the total distance travelled is 15 s, then

A car, starting from rest, accelerates at the rate f through a distance s, then continues at constant speed for time t and then decelerates at the rate f/ 2 to come to rest. If the total distance travelled is 15 s, then

A car,starting from rest, accelerates at the rate f through a distance s, then continuous at constant speed for time t and then decelerates at the rate f/2 come to rest. If the total distance traversed is 5 s,then :

A car starting from rest, accelerates at the rate of f through a distance S, then continues at constant speed for time t and declerates at the rate f/2 to come to rest. If the total distance travelled is 15 S then S =

A bus starting from rest, accelerates at the rate of f through a distance S, then continues at constant speed for time t and declerates at the rate f/2 to come to rest. If the total distance travelled is 15 S then S =

A car, starting from rest, accelerates at the rate (f) through a distance (S), then continues at constant speed for some time (t) and then decelerates at the rate f//2 to come to rest. If the total distance is 5 S , then prove that S=1/2/ ft^(2) .

A car, starting from rest, accelerates at the rate (f) through a distance (S), then continues at constant speed for some time (t) and then decelerates at the rate f//2 to come to rest. If the total distance is 5 S , then prove that S=1/2/ ft^(@) .