A spectral line in the spectrum of H atom has a wavelength of `15222.22 cm^(-1)` .The transition responsible for this rediation is (Rydherg constant `R = 10977 cm^(-1)`

A spectral line in the Lyman series of hydrogen atom has a wave number of 82200 cm^(-1) .What transition is resposible for the radiation ? (R = 109600 cm^(-1))

Wavelength of the first line of Paschen series is - (R = 109700 cm^-1 )

Difference in wavelength of two extreme lines of H-atom in Balmer region is (where R_(H) is Rydberg constant ):

Every series of hydrogen spectrum has an upper and lower limit in wavelength. The spectral series which has an upper limit of wavelegnth equal to 18752 Å is (Rydberg constant R = 1.097 xx 10^(7) per metre)

Calculate the shortest and longest wavelength I hydrogen spectrum of Lyman series. or Calculate the wavelength of the first line and the series limit for the Lyman series of hydrogen. (R_(H)=109678cm^(-1)) .