`N_(2)+3H_(2)hArr2NH_(3)`
Which is correct statement if `N_(2)` is added at equilibrium condition?

N_(2)+3H_(2) hArr 2NH_(3) Which of the following statements is correct if N_(2) added at equilibrium condition?

For the reaction, N_(2)+3H_(2)hArr2NH_(3) , in a vessel equal moles of N_(2) and H_(2) are mixed to attain equilibrium. At equilibrium:

N_(2)(g) and H_(2)(g) are allowed to react in a closed vessel at given temp. and pressure for the formation of NH_(3)(g),[N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g)+22.4kcal] If he (g) is added at equilibrium at constant pressure than which is/are correct ?

For the synthesis of ammonia by the reaction N_(2)+3H_(2)hArr2NH_(3) in the Haber's process ,the attainment of equilibrium is correctly predicated bt the curve

For N_(2)+3H_(2)hArr 2NH_(3) , 1 mole N_(2) and 3 mol H_(2) are at 4 atm. Equilibrium pressure is found to be 3 atm. Hence, K_(p) is