What is the last digit of `3^(3^(4n)) +1`, where n is a natural number?

What is the last digit of 3^(3n)+1, where n is a natural number?

The last digit of 3^(3^(4n))+1 , is

The last digit of (3^(P)+2), where P=3^(4n+2) is

If the sum of the digits of a number 10^(n) - 1 , where n is a natural number, is equal to 3798, then what is the value of n ?

What is the sum of the coefficients of first and last terms in the expansion of (1 + x)^(2n) , where n is a natural number?

If the sum of the digits of a number (10^(n)-1) is 4707, where n is a natural number,then the value of n is :

The unit digit of (316)^(3^(4n)) + 1 is :

The unit digit of (316^3)^(4n) + 1 is

Is the units digit in the value of 6^n where 'n' is a natural number is zero? Justify your answer.