If A and B are square matrics of the same order then `(A+B)^2=? `

If A and B are square matrices of the same order, then

If A and B are square matrices of the same order then (A+B)^2=A^2+2AB+B^2 implies

If A and B are square matrices of the same order then (A+B)^2=A^2+2AB+B^2 implies (A) AB=0 (B) AB+BA=0 (C) AB=BA (D) none of these

If A and B are square matrices of the same order then (A+B)^2=A^2+2AB+B^2 implies (A) both AB and BA are defined (B) (AB)^t=B^tA^t (C) (AB)^-1=B^-1A^-1 if |A|!=0 (D) AB=BA

If A and B are square matrices of same order, then

If A and B are square matrics of the same order then (A+B)(A-B)=?

If A and B are two square matrices of the same order then (A-B)^2 is (A) A^2-AB-BA+B^2 (B) A^2-2AB+B^2 (C) A^2-2BA+B^2 (D) A^2-B^2

If A and B are two square matrices of the same order then (A-B)^2 is (A) A^2-AB-BA+B^2 (B) A^2-2AB+B^2 (C) A^2-2BA+B^2 (D) A^2-B^2

Fill in the blanks: If A and B are square matrices of the same order then (A+B)' = ………….. .

Fill in the blanks: If A and B are square matrices of the same order then (AB)' = …………../