`f(x)=("lim")_(n->oo)x/(x^(2n)+1)dotT h e n ,` A. `f(1^+)+f(1^(-1))=0` B. `f(1^+)+f(1^-)+f(1)=3/2` C. `f(-1^+)+f(-1^-)=-1` D. `f(1^+)+f(-1^-)=0`

f(x)=(lim)_(n rarr oo)(x)/(x^(2n)+1) Then ,Af(1^(+))+f(1^(-1))=0Bf(1^(+))+f(1^(-))+f(1)=(3)/(2)cf(-1^(+))+f(-1^(-))=-1Df(1^(+))+f(-1^(-))=0

If f(x)=|(log)_e x| , then (a) f'(1^+)=1 (b) f^'(1^(-))=-1 (c) f'(1)=1 (d) f'(1)=-1

If f(x)=lim_(n->oo)n(x^(1/n)-1),t h e nforx >0,y >0,f(x y) is equal to : (a) f(x)f(y) (b) f(x)+f(y) (c) f(x)-f(y) (d) none of these

If f(x)=|(log)_(e)x|, then (a) f'(1^(+))=1 (b) f'(1^(-))=-1( c) f'(1)=1(d)f'(1)=-1

If f(x)=lim_(n->oo) {2x+4x^3+...+2n x^(2n-1)}, 0 < x< 1 and int f(x) dx = F(x) and F(1/sqrt(2)) = 2, then (i) F(0)=1, (ii) F(1/2)=4/3, (iii) F(0)=-1, (iv) F(-1/2)=4/3

If f(x)=lim_(n->oo)n(x^(1/n)-1),then for x >0,y >0,f(x y) is equal to : (a) f(x)f(y) (b) f(x)+f(y) (c) f(x)-f(y) (d) none of these

If f(x)=x^3-x^2+100x+2002 ,t h e n a) f(1000)>f(1001) b) f(1/(2000))>f(1/(2001)) c) f(x-1)>f(x-2) d) f(2x-3)>f(2x)

f(x)=(x)/(x-1) then (f(a))/(f(a+1)) is equal to a.f(-a) b.f(1/a) c.f(a^(2)) d.f (-(a)/(a-1))