For the equation `40/[x-1]-160/[x-4]-200/[x-5]+320/[x-8]=6x^2-27x` (A) Number of real solutions of above equation is 3 (B) If E denotes the product of non-zero real or complex roots of the equation, then sum of divisors of E is 2904 (C) If S denotes the set of all real roots of the equation then, sum of elements of S taken two at a time is 81 (D) If `alpha_1,alpha_2 in R` be two roots of the equation such that `log_[alpha_2](2alpha_1)` is defined then it must be 1.