What is the principal argument of `)-1-i),where i=sqrt(-1)` ?

Find the principal argument of (-2i).

The principal argument of (3)/(-1 + i) is

Principal argument of z=-1-i sqrt(3)

If z=sqrt(3)-2+i , then principal value of argument z is (where i=sqrt(-1) (1) -(5pi)/(12) (2) pi/(12) (3) (7pi)/(12) (4) (5pi)/(12)

The principal argument of 2z^(2)+1-sqrt(3)i=0

Find the principal argument of ( 1+i sqrt(3))^(2) .

Find the principal argument of (1+i sqrt(3))^(2)

If z=sqrt(3)-2+i, then principal value of argument z is (where i=sqrt(-1)-(5 pi)/(12)(2)(pi)/(12) (3) (7 pi)/(12) (4) (5 pi)/(12)