`CH_(3)-underset(Br)underset(|)overset(Br)overset(|)C-undersset(Br)underset(Br)underset(|)overset(Br)overset(|)C-CH_(3)i=overset(xNaNH_(2))to overset(yCH_(3)I)to CH_(3)-C-=C--=c-CH_(3)`
xand y mole consumed .
value of x+y=

CH_3-underset(Br)underset(|)overset(Br)overset(|)C-underset(Br)underset(|)overset(Br)overset(|)C-CH_3overset(xNaNH_(2))to overset(yCH_(3)I)to CH_(3)-C-=C-C-=C-CH_(3) value of x+y =

underset(" x and y mole consumed.")(CH_3-overset(Br)overset(|)underset(Br)underset(|)C-overset(Br)overset(|)underset(Br)underset(|)C -CH_3) overset(xNaNH_2) rarr (y CH_3I) rarr CH_3-C -= C-C-= - CH_3 x and y mole consumed . Value of x + y =

CH_(3)underset(Br)underset(|)CH-overset(CH_(3))overset(|)underset(OH)underset(|)(C)-C-O-CH_(3)

Ph - underset(underset(Br)|)overset(overset(Br)|)C - CH_3 overset(x Na NH_2)(to) A overset(CH_3 I)(to) Ph - C -= C - CH_3 The sum of x and y is

In the reaction : CH_(3) - underset(Br)underset(|)overset(Br)overset(|)(C) - underset(Br)underset(|)overset(Br)overset(|)(C) - H overset(Zn)rarr the product is :

CH_(3)-Br+NaO-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH_(3)to ?

CH_(3)-underset(Br)underset(|)CH-CH_(2)-overset(O)overset(||)C-CH_(3)underset(Delta)overset(N_(2)H_(4),overset(Ө)OH)rarr product :