Home
Class 12
PHYSICS
In an experiment with a potentiometer to...

In an experiment with a potentiometer to measure the internal resistance of a cell. when the cell in the secondary circuit is by shounted by `5 Omega`, the null point is at `220 cm`. When the cell is shunted by `20 Omega ` the null point is at `300 cm`. Find the internal resistance of the cell.

Promotional Banner

Similar Questions

Explore conceptually related problems

In an experiment with potentiometer to measure the internal resistance of a cell, when the cell is shunted by 5Omega , the null point is obtained at 2m. when cell is shunted by 20Omega the null point is obtained at 3m. The internal resistance of cell is

In an experiment with potentiometer to measure the internal resistance of a cell when the cell is shunted by 5Omega the null point is obtained at 2m .When the cell is shunted by 10Omega the null point is obtained at 3m .The internal resistance of the cell is

In an experiment to determine the internal resistance of a cell, the null point is obtained at 2 cm, when the cell is shnted by a resistance of 5Omega . When the cell is shunted by a resistance of 20Omega , the null point is obtained at 3 cm. Find the internal resistance of the cell.

In an experiment to measure the internal resistance of a cell by potentiometer, it is found that the balance point is at a length of 2 m when the cell is shunted by a 4Omega resistance and at 3 m when cell is shunted by a 8Omega resistance. The internal resistance of cell is -

In an experiment to measure the internal resistance of a cell by potentiometer, it is found that the balance point is at a length of 2 m when the cell is shunted by a 4Omega resistance and at 3 m when cell is shunted by a 8Omega resistance. The internal resistance of cell is -