Evaluate `|{:(265, 240, 219),(240, 225, 198), (219, 198, 181):}|`

Without expanding evaluate the determinant =|(265, 240, 219), (240, 225, 198), (219, 198 ,181)| .

The value of Delta by using the properties of determinant where Delta = |{:(265,240,219),(240,225,198),(219,198,181):}| is

The value of Delta by using the properties of determinant where Delta = |{:(265,240,219),(240,225,198),(219,198,181):}| is

|[265,240,219],[240,225,198],[219,198,181]|=0

Find the values of the following determinants : (i) |{:(12,3,4),(16,5,0),(21,-1,2):}| (ii) |{:(256,240,219),(240,225,198),(219,198,181):}| (iii) |{:(17,19,24),(6,8,13),(-1,1,6):}| (iv) |{:(67,19,21),(39,13,14),(81,24,26):}| (v) |{:(1,omega,omega^(2)),(omega,omega^(2),1),(omega^(2),omega,1):}|" where "omega "is a cube root of unity". (iv) |{:(1,x,y),(0,(2pi)/5,sin(pi)/10),(0,sin((2pi)/5),cos(pi)/10):}|

Using properties of determinants or otherwise evaluate {:|(18, 40, 89), (40, 89, 198),(89, 198, 440)|:}

Select and write the correct answer from the given alternatives in each of the following:If triangle=|(265,240,219),(240,225,198),(219,198,181)| ,then triangle=

Prove that |[265,240,219],[240,225,198],[219,198,181]|=0

Prove that |[265,240,219] , [240,225,198] , [219,198,181]|=0

using properties of determinants evaluate |{:(18,,40,,89),(40 ,,89,,198),( 89,, 198,,440):}|