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1 taunt Seena 2 Cofna...

1 taunt Seena 2 Cofna

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If A=[[1, 2, 2], [2, 1, 2], [2, 2, 1]] and A^(-1) exist and not equal to 0, then (A^(2)-4A)A^(-1)=

If A=[[1, 2, 2], [2, 1, 2], [2, 2, 1]] and A^(-1) exist and not equal to 0, then (A^(2)-4A)A^(-1)=

The x-coordinates of the vertices of a square of unit area are the roots of the equation x^2-3|x|+2=0 . The y-coordinates of the vertices are the roots of the equation y^2-3y+2=0. Then the possible vertices of the square is/are (a)(1,1),(2,1),(2,2),(1,2) (b)(-1,1),(-2,1),(-2,2),(-1,2) (c)(2,1),(1,-1),(1,2),(2,2) (d)(-2,1),(-1,-1),(-1,2),(-2,2)