A balloon starts rising from the surface of the Earth. The ascertion rate is constant and equal to `v_0`. Due to the wind the balloon

A balloon starts rising from the earth's surface. The ascension rate is constant and equal to v_(0) . Due to the wind. The balloon gathers the horizontal velocity component v_(x)=ky , where k is a constnat and y is the height of ascent. Find how the following quantities depednd on the height of ascent. (a) the horizontal drift of the balloon x (y) (b) the total tangential and normal accelrations of the balloon.

A balloon starts rising from the earth's surface. The ascension rate is constant and equal to v_(0) . Due to the wind. The balloon gathers the horizontal velocity component v_(x)=ky , where k is a constnat and y is the height of ascent. Find how the following quantities depednd on the height of ascent. (a) the horizontal drift of the balloon x (y) (b) the total tangential and normal accelrations of the balloon.

A balloon starts rising from the surface of the earth with a verticle component of velocity v_(0) . The baloon gathes a horizontal velocity v_(x)=lambda_(y) , where lambda is a constant and y is the height from the surface of earth, due to a horizontaln wind. determine (a) the equation of trajectory and (b) the tangential, normal and total acceleration of the balloon as a function of y .

A balloon starts rising from the surface of the earth with vertical component of velocity v_(0) . The balloon gathers a horizontal velocity v_(x) = ay , where a is a constant and y is the height from the surface of the earth, due to a horizontal wind. Determine (a) the equation of trajectory of the balloon. (b) the tangential, normal and total acceleration of the balloon as function of y.

A balloon starts rising from the ground with an acceleration of 1.25ms^-2 . After 8 seconds, a stone is released from the balloon. After releasing, the stone will:

A balloon starts rising from the ground with an acceleration of 1.25ms^-2 . After 8 seconds, a stone is released from the balloon. After releasing, the stone will:

A balloon starts from the state of rest from the ground with constant acceleration g/n. after time T, a stone is dropped from the balloon. If stone takes time T to reach the ground then calculate value of n.

A balloon starts rising from thee ground with an acceleration of 1.25 m//s^(2) . After 8 s, a stone is released from the balloon. The stone will (taking g = 10 ms^(-2) )