Velocity time equation of a particle moving in a straight line is `v=2t-4` for `tle2s` and `v=4-2t` for `tgt2`.The distance travelled by the particle in the time interval from `t=0` to `t=4s ` is (Here `t` is in second and `v` in m/s)

Velocity-time equation of a particle moving in a straight line is v=2t-4 for t le 2s and v= 4-2t for 1 gt 2s . The distance travelled ( in meters) by the particle in the time interval from t=0 to t=4s is 4k. The value of 'k' is ( Here t is in second and v in m/s) :

If velocity (in ms^(-1) ) varies with time as V = 5t, find the distance travelled by the particle in time interval of t = 2s to t = 4 s.

If the distance s travelled by a particle in time t is s=a sin t +b cos 2t , then the acceleration at t=0 is

The velocity 'v' of a particle moving along straight line is given in terms of time t as v=3(t^(2)-t) where t is in seconds and v is in m//s . The distance travelled by particle from t=0 to t=2 seconds is :

The velocity 'v' of a particle moving along straight line is given in terms of time t as v=3(t^(2)-t) where t is in seconds and v is in m//s . The distance travelled by particle from t=0 to t=2 seconds is :

The velocity v of a particle at any instant t moving in a straight line is given by v=s +1 where s meter is the distance travelled in t second what is the time taken by the particle to cover a distacne of 9m ?

A particle moving along a straight line has the relation s=t^(3)+2t+3 , connecting the distance s describe by the particle in time t. Find the velocity and acceleration of the particle at t=4 sec.

A particle moves along a straight line its velocity dipends on time as v=4t-t^(2) . Then for first 5 s :