In the given figure, ABCD is a square of side `14cm`.Semicircles are drawn with each side of square as diameter. Find the area of the shaded region.

Explanation

Let `A_1` and `A_2` are area of the shaded and unshaded regions respectively.

Let side of the square is `a` cm.

Then,

`A_1+A_2 = a^2->(1)`...[Area of square `= a^2` ]

`Also, A_1/4+A_2/2 = pi/2(a/2)^2 = (pia^2)/8`

`=>A_1+2A_2 = (pia^2)/2->(2)`

From (1),

`=>A_1+2(a^2-A_1) = (pia^2)/2`

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