A series combination of `L` and `R` is connected to a battery of emf `E` having negligible internal resistance. The final value of current depeds upon

A series combination of L and R is connected to a battery of emf E having negligible internal resistance. The final value of current depends upon

Three resistances 2Omega, 4Omega, 5Omega are combined in series and this combination is connected to a battery of 12 V emf and negligible internal resistance. The potential drop across these resistances are

Three resistances 2Omega, 4Omega, 5Omega are combined in series and this combination is connected to a battery of 12 V emf and negligible internal resistance. The potential drop across these resistances are

Three resistors 2Omega, 4Omega and 5Omega are combined in parallel. This combination is connected to a battery of emf 20V and negligible internal Resistance. The total current drawn from the battery is

Three resistors 2Omega, 4Omega and 5Omega are combined in parallel. This combination is connected to a battery of emf 20V and negligible internal Resistance. The total current drawn from the battery is

Three resistors 1Ω, 2Ω and 3Ω are combined in series and the combination is connected to a battery of emf 12 V and negligible internal resistance, obtain the potential drop across each resistor.

(a) Three resistors 2 Omega, 4 Omega and 5 Omega are combined in series. What is the total resistance of the combination ? (b) If the combination is connected to a battery of emf 20 V and negligible internal resistance, determine the current through each resistor, and the total current drawn from the battery.