Given standard electode potenitals
` Fe^(2+) + 2e^(-) rarr Fe, E^@ =- 0. 44 V ` ………………(1)
` Fe^(3+) + 2e^(-) rarr Fe, E^@ =- 0. 036 V` ………….(2)
The standard electrode pptential `E^@ ` for
`Fe^(2+) + e rarr Fe^(2+)` is.

Given, standard electrode potentials, {:(Fe^(3+)+3e^(-) rarr Fe,,,E^(@) = -0.036 " volt"),(Fe^(2+)+2e^(-)rarr Fe,,,E^(@) = - 0.440 " volt"):} The standard electrode potential E^(@) for Fe^(3+) + e^(-) rarr Fe^(2+) is :

Given, standard electrode potentials, {:(Fe^(3+)+3e^(-) rarr Fe,,,E^(@) = -0.036 " volt"),(Fe^(2+)+2e^(-)rarr Fe,,,E^(@) = - 0.440 " volt"):} The standard electrode potential E^(@) for Fe^(3+) + e^(-) rarr Fe^(2+) is :

Given, standard electrode potentials, {:(Fe^(3+)+3e^(-) rarr Fe,,,E^(@) = -0.036 " volt"),(Fe^(2+)+2e^(-)rarr Fe,,,E^(@) = - 0.440 " volt"):} The standard electrode potential E^(@) for Fe^(3+) + e^(-) rarr Fe^(2+) is :

Given, standard electrode potentials Fe^(2+) +2e^(-) rarr Fe, E^(@)=-0.440 V Fe^(3+)+3e^(-) rarr Fe, E^(@)=- 0.036 V The standarde potential (E^(@)) for Fe^(2+)+e^(-) rarr Fe^(2+) , is

The standard reduction for the following reactions are : Fe^(3+) + 3e^(-) rarr Fe with E^(@) = - 0.036 V Fe^(2+) + 2e^(-) rarr Fe with E^(@) = - 0.44 V What would be the standard electrode potential for the reaction Fe^(3+) + e^(-) rarr Fe^(2+) ?

Standard electrode potentials of Fe^(2+) + 2e to Fe and Fe^(3+) + 3e to Fe are -0.440V and -0.036V respectively. The standard electrode potential (E^@) for Fe^(3+) +e to Fe^(2+) is

Standard electrode potentials are : Fe^(2+) "|" Fe (E^(@) = - 0.44 V), Fe^(3+) "|" Fe^(2+) (E^(@) = 0.77 V) Fe^(2+), Fe^(3+) and Fe blocks are kept together, then

Standard electrode potentials are : Fe^(2+) "|" Fe (E^(@) = - 0.44 V), Fe^(3+) "|" Fe^(2+) (E^(@) = 0.77 V) Fe^(2+), Fe^(3+) and Fe blocks are kept together, then