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[" 5.At "320K" ,a gas "A(2)" is "20%" di...

[" 5.At "320K" ,a gas "A_(2)" is "20%" dissociated to "A(g)" ."],[" The standard free energy change at "320K" and "],[1atm" in "Jmol^(-1)" is approximately: "],[(R=8.314JK^(-1)mol^(-1)ln2=0.693;ln3=1.098)],[" (JEE Main-April "16,2018" -Online) "],[[" 1) "1844," 2) "2068," 3) "4281," 4) "4763]]

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At 320 K, a gas A_(2) is 20% dissociated to A(g). The standard free energy change at 320 K and 1 atm in J mol^(-1) is approximately : (R =8.314 Jk^(-1)"mol"^(-1), "In" 2=0.693, "In" 3 = 1.098)

At 320 K, a gas A_(2) is 20% dissociated to A(g). The standard free energy change at 320 K and 1 atm in J mol^(-1) is approximately : (R =8.314 Jk^(-1)"mol"^(-1), "In" 2=0.693, "In" 3 = 1.098)

Kinetic energy in Kj of 280 g of N_(2) at 27^(@)C is approximately (R = 8. 314 J mol ^(-1) K ^(-1))

The standard free energy change of a reaction is DeltaG^(@)=-kJ//mol^(-1) at 298 K. Calculate the value of log_(10)K_(p) (R=8.314JK^(-1)mol^(-1))

The standard free energy change of a reaction is DeltaG^(@)=-115kJ//mol^(-1) at 298 K. Calculate the value of log_(10)K_(p) (R=8.314JK^(-1)mol^(-1))

The standard free energy change of a reaction is DeltaG^(@)=-115kJ//mol^(-1) at 298 K. Calculate the value of log_(10)K_(p) (R=8.314JK^(-1)mol^(-1))

The standard free energy change of a reaction is DeltaG^(@)=-115 at 298K. Calculate the equilibrium constant K_(P) in log K_(P).(R=8.314JK^(-1)mol^(-1))