`x^2+2x+3x=1`

Solve (x^2-2x-3)/(x+1)=0.

Solve (x^2-2x-3)/(x+1)=0.

Solve (x^2-2x-3)/(x+1)=0.

Solve (x^2-2x-3)/(x+1)=0.

Determine the value of constant k so that the function f(x) = {{:((x^2 - 2x - 3)/(x + 1)"," ,"if " x != 1),(k",","if " x = 1):}

Examine the continuity of the following function at the given point : f(x) = {(x^2 - 2x + 3, x 1):} x = 1.

Let f(x) = {((x^(2) -2x -3)/(x + 1)","," when " x != -1),(" k,"," when " x = -1):} If f(x) is continuous at x = -1 then k = ?

Simplify each of the following 3x^(2) + 2(x + 2) - 3x (2x + 1)

Simplify the following: 3x^2 + x (x+2) -3x (2x +1)

Integrate the following: 6x + 5x^2 - 2x^3 + (1/x^2)