The angle of dip at a place is `60^(@)`. At this place the total intensity of earth's magnetic field is `0.64` units. The horizontal intensity of earth's magnetic field at this place is

The angle of dip at a place is 40.6^(@) and the intensity of the vertical component of the earth's magnetic field V=6xx10^(-5) Tesla. The total intensity of the earth's magnetic field (I) at this place is

The angle of dip at a place is 40.6^(@) and the intensity of the vertical component of the earth's magnetic field V=6xx10^(-5) Tesla. The total intensity of the earth's magnetic field (I) at this place is

How is the horizontal component of earth's magnetic field related with the total intensity of earth's magnetic field and the angle of dip ?

The angle of dip at a place is 60^@ N. find the value of the total intensity of the earth's magnetic field. [Given H = 3.6 xx 10^-5 Tesla ]

The angle of dip at a place is 30^(@) and the horizontal component of earth ' s magnetic field at that place is 0.39 CGS units . Determine the vertical component of earth's magnetic field at that place .