`bar a+2 bar b+3bar c=bar 0 and bar axxbar b+bar b xx bar c+bar cxx bara = iota (bar b xx bar c)`,then `iota=`

if bar a+2 bar b+3bar c=bar 0 then bar axxbar b+bar b xx bar c+bar cxx bara = lambda (bar b xx bar c) ,where lambda=

bar(a)+2bar(b)+3bar(c)=bar(0) and bar(a)xxbar(b)+bar(b)xxbar(c)+bar(c)xxbar(a)=iota(bar(b)xxbar(c)), then iota=

bar(a)+2bar(b)+3bar(c)=bar(0) and bar(a)xxbar(b)+bar(b)xxbar(c)+bar(c)xxbar(a)=rho(bar(b)xxbar(c)), then rho=

Prove that [[bar a xx bar p, bar b xx bar p, bar cxx bar r]]+[[bar axx bar q, bar b xx bar r, bar c xx bar p]]+[[bar a xx bar r, bar b xx bar p,bar c xx bar q]]=0

If bar a = 2 bar I + bar j - bar k, bar b = - bari + 2 bar j - 4 bar k and bar c = bar I + bar j + bar k , then find ( bar a xx bar b) cdot (bar b xx bar c) .

If bar(a)+2bar(b)+3bar(c)=bar(0) then bar(a)xxbar(b)+bar(b)xxbar(c)+bar(c)xxbar(a)=

If bar r=l(bar b xx bar c)+m(bar c xx bar a)+n(bar a xx bar b) and [bar a bar b bar c]=2 , then l+m+n is equal to

bar a, bar b, bar c are three vectros, then prove that: (bar a xx bar b) xx bar c = (bar a. bar c) bar b-(bar b. bar c) bar a.

(d) answer ANY one question :1. bar a, bar b and bar c be three vectors such that bar a +bar b+ bar c =0 and |bar a|=1, |bar b|=4,|bar c |=2 . Evlautae bar a.bar b + bar b.bar c+bar c.bar a .

If bar(a).bar(b) = bar(a).bar(c ) and bar(a) xx bar(b) = bar(a) xx bar(c ), bar(a) != 0 , then show that bar(b) = bar(c ) .