[" 64.Phosphoric acid "H_(3)PO_(4)" can be neutralised to: "],[[" (a) "HPO_(4)^(2-)," (b) "PO_(4)^(3-)," (c) "H_(2)PO_(4)^(-)," (d) "HPO_(3)^(2-)]]

Phosphoric acid ionises as : H_(3)PO_(4)overset(K_(1))hArr H^(+)+H_(2)PO_(4)^(-) H_(2)PO_(4)^(-)overset(K_(2))hArr H^(+)+H_PO_(2)^(-) H_(2)PO_(4)^(2-)overset(K_(3))hArr H^(+)+PO_(3)^(-) The equilibrium constant, K for the reaction : H_(3)PO_(4)hArr 3H^(+)+PO_(4)^(3-) is :

The anhydride of acid H_(3)PO_(4) and HPO_(3) are:

Three reactions involving H_(2)PO_(4)^(-) are given below : (i) H_(3)PO_(4)+H_(2)Orarr H_(3)O^(+)+H_(2)PO_(4)^(-) (ii) H_(2)PO_(4)^(-)+H_(2)OrarrHPO_(4)^(2-)+H_(3)O^(+) (iii) H_(2)PO_(4)^(-)+OH^(-)rarr H_(3)PO_(4)+O^(2-) In which of the above does H_(2)PO_(4)^(-) act as an acid?

H_(3)PO_(3) is ..... acid

H_(3)PO_(3) is a _______acid.

H_(3)PO_(3) is ..... acid

What is the equivalent weight of phosphoric acid (H_(3) PO_(4)) according to the equation NaOH + H_(3) PO_(4) rarr NaH_(2) PO_(4) + H_(2)O