For a cell terminal potential difference is 2.2 V when circuit is open and reduces to 1.8V when cell is connected to a resistance of R=`5Omega` then determine internal resistance of cell is:-

For a cell, the terminal potential difference is 2.2 V , when circuit is open and reduces to 1.8 V . When cell is connected to a resistance R=5Omega , the internal resistance of cell (R) is

For a cell, the terminal potential difference is 2.2 V , when circuit is open and reduces to 1.8 V . When cell is connected to a resistance R=5Omega , the internal resistance of cell (R) is

For a cell, the terminal potential difference is 2.2 V , when circuit is open and reduces to 1.8 V . When cell is connected to a resistance R=5Omega , the internal resistance of cell (R) is

For a Cell, the terminal potential difference is 2.2 V when circuit is open and reduces to 1.8 V, when cell is connected to a resistance R = 5Omega . The internal resistance of cell (r ) is

A cell of emf 2V produces 0.3A current when connected to a resistor of 5Omega . Calculate the terminal voltage and internal resistance of the cell.

The emf of a cell is 2 V. When the terminals of the cell is connected to a resistance 4Omega . The potential difference across the terminals, if internal resistance of cell is 1Omega is

The terminal potential difference for a cell is 8.5 V when current is 2A and 9 V when current is 1.5A. What is the internal resistance of cell ?

The reading on a high resistance voltmeter. When a cell is connected across it is 2.2 V . When the terminals of the cell are connected to a resistance of 5 Omega the voltmeter reading drop to 1.8 V . Find the internal resistance of the cell.