Tangents are drawn to the ellipse `x^2/9+y^2/5 = 1` at the end of latus rectum. Find the area of quadrilateral so formed

Tangents are drawn to the ellipse x^(2)/9+y^(2)/5=1 at the ends of latus rectum. The area of the quadrilateral formed, is

Tangents are drawn to the ellipse (x^2)/(9)+(y^2)/(5)=1 at the ends of both latusrectum. The area of the quadrilateral so formed is

Tangents are drawn to the ellipse (x^2)/(25) + (y^2)/(16) = 1 at all the four ends of its latusrectum. Then, the area (in sq units) of the quadrilateral formed by these tangents is

Find the equation of the tangent and normal to the ellipse 9x^2+16y^2=144 at the end of the latus rectum in the first quadrant.

Tangents are drawn to the ellipse 5x^(2)+ 9y^(2)=45 at the four ends of two latera recta. The area (in square unit) of the quadrilateral so formed is-

The tangent to the ellipse (x^(2))/(25)+(y^(2))/(16)=1 at the end of the latus rectum, in the second quadrant, meets the coordinate axes at

The equations of the tangents to the ellipse 9x^(2)+16y^(2)=144 at the ends of the latus rectum are