Two dielctric slabs of constant `K_(1)` and `K_(2)` have been filled in between the plates of a capacitor as shown below. What will be the capacitance of the capacitor ?

Two dielectric slabs of constant K1 and K2 have been filled in between the plates of a capacitor as shown below. What will be the capacitance of the capacitor

Two dielectric slabs of dielectric constant K_1 and K_2 are filled in between the two plates, each of area A, of the parallel plate capacitor as shown in the figure. What will be the capacitance of the capacitor

Two dielectric slabs of dielectric constants K_(1) and K_(2) are filled in between the two plates, eachof area A of the parallel plate capacitor as shown in the figure. Find the net capacitance of the capacitor.

Two dielectric slabs of dielectric constants K_1 and K_2 are filled in between two plates each of area A, of a parallel plate capacitor. Find net capacitance.

Two material having the dielectric constans K_(1) and K_(2) are filled between two parallel plates of a capacitor. where area of each plate is A and the distance between the plates is d . The capacitor of the capacitor is:

A parallel plate capacitor consists of two identical metal plates. Two dielectric slabs having dielectric donstants k_1 and k_2 are introduced in the space between two plates as shown below. Show that capacity of capacitor in arrangement (a) is given by , C = (epsilon_0 (k_1+k_2)A)/(2d)

Find the capacitance between A and B if two dielectric slabs (each of thickness d) of dielectric constants K_(1) and K_(2) and areas K_(1) and K_(2) and inserted between the plates of a parallel plate capacitor of plate area A . .

Find the capacitance between A and B if two dielectric slabs (each of thickness d) of dielectric constants K_(1) and K_(2) and areas K_(1) and K_(2) and inserted between the plates of a parallel plate capacitor of plate area A . .

A parallel-plate capacitor with plate area A has separation d between the plates. Two dielectric slabs of dielectric constant K_1 and K_2 of same area A//2 and thickness d//2 are inserted in the space between the plates. The capacitance of the capacitor will be given by :