The line which is parallel to `5x + 12y + 13 = 0` and `10x + 24y + 25=0` distance of and mid way between them is at a units (approx.) from origin.

Find the equation of two lines parallel to 5x -12y + 26 = 0 at a distance of 4 units from it.

The distance between the parallel lines 5x - 12y - 14 = 0 and 5x - 12y + 12 = 0 is equal to

The equation of the lines parallel to 5x-12 y+26=0 and at a distance of 4 units from it

Find the distance between two parallel lines 5x + 12y -30 =0 and 5x+12y - 4=0

The equation of the line which is parallel to 5x+12y+1=0 and 5x+12y+7=0 and lying midway between them is ( i )5x+12y+13=0(ii)5x+12y-4=0 (iii) 5x+12y+4=0(iv)5x+12y-6=0

The equation n s of the lines parallel to 5x-12 y+26=0 and at a distance of 4 units from it are:

The distance between the parallel lines 5x-12y-14=0 and 5x-12y+12=0 is equal to

The distance between the parallel lines 5x+2y+7=0 and 5x+2y+4=0 is