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" (1) "x+y=sec^(-1)(x-y)...

" (1) "x+y=sec^(-1)(x-y)

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Find (dy)/(dx),quad if x+y=sec^(-1)(x-y)

Draw the graph of y="cosec"("cosec"^(-1)x)" or "y=sec(sec^(-1)x) .

Draw the graph of y="cosec"("cosec"^(-1)x)" or "y=sec(sec^(-1)x) .

Draw the graph of y="cosec"("cosec"^(-1)x)" or "y=sec(sec^(-1)x) .

Draw the graph of y="cosec"("cosec"^(-1)x)" or "y=sec(sec^(-1)x) .

Draw the graph of y="cosec"("cosec"^(-1)x)" or "y=sec(sec^(-1)x) .

The area of the closed region bounded by y=sec^(-1)x, y ="cosec"^(-1)x and the line x-1=0 is

If sec^(-1) x = cosec^(-1) y , then find the value of cos^(-1).(1)/(x) + cos^(-1).(1)/(y)

If sec^(-1) x = cosec^(-1) y , then find the value of cos^(-1) . 1/x + cos ^(-1) . 1/y .

If sec^(-1) x = cosec^(-1) y , then find the value of cos^(-1).(1)/(x) + cos^(-1).(1)/(y)