(sin3 theta)/(2cos2 theta+1)=(1)/(2)" if "

(sin3 theta)/(1+2cos2 theta)

(sin3theta)/(2cos2theta+1)=(1)/(2) if (n in Z)

(sin3theta)/(2cos2theta+1)=(1)/(2) if (n in Z)

(sin3theta)/(2cos2theta+1)=(1)/(2) if (n in Z)

1-(sin^(2) theta)/(1+cos theta) + (1+cos theta)/(sin theta) - (sin theta)/(1-cos theta) - (1)/(sec theta)=

1- (sin ^ (2) theta) / (1 + cos theta) + (1 + cos theta) / (sin theta) - (sin theta) / (1-cos theta) - (1) / (sec theta)

(sin^(2) theta)/(1-cos theta)-(cos^(2) theta)/(1-sin theta)=cos theta-sin theta

Prove : (cos^2 theta)/(1-tan theta) + (sin^3 theta)/(sin theta-cos theta) = 1 + sin theta cos theta

Prove that (1)/(2){(sin theta)/(1+cos theta)+(1+cos theta)/(sin theta)}=(1)/(sin theta)