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cos(x)cos(2x)cos(3x)=1/4. Find the gener...

`cos(x)cos(2x)cos(3x)=1/4`. Find the general solution.

Text Solution

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`cos(x)cos(2x)cos(3x) = 1/4`
`=>4cos(x)cos(2x)cos(3x) = 1`
`=>((2cosxsinx)/sinx)*2cos(2x)cos(3x) = 1`
`=>(2sin2xcos 2x cos 3x) = sinx`
`=>sin4xcos3x = sinx`
`=>2sin4xcos3x = 2sin x`
`=>sin7x+sinx = 2sinx`
`=> sin7x = sinx->(1)`
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