Find the co-ordinates of the centre of the circle passing through the points `(0,0)`,`(-2,1)` and `(-3,2)`. Also find its radius.

Explanation

Let `(a,b)` is the center of the circle and `r` is the radius of the circle.

Then, we have,

`(x-a)^2+(y-b)^2 = r^2`

As this circle is passing through `(0,0)`,

`:. (0-a)^2+(0-b)^2 = r^2`

`=>a^2+b^2 = r^2->(1)`

Now, equation of the circle is,

`x^2+y^2-2ax-2by = 0`

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