Find `(dy)/(dx)`, when
`x=costheta+cos2 theta,y=sin theta+sin2theta`

Find dy/dx when x = cos theta + cos 2 theta, y = sin theta + sin 2 theta)

Find (dy)/(dx) , if x=costheta-cos2theta , y=sintheta-sin2theta

If x and y are connected parametrically by the equations given,without eliminating the parameter,Find (dy)/(dx)x=cos theta-cos2 theta,y=sin theta-sin2 theta

Find (dy)/(dx), when x=a(cos theta+theta sin theta) and y=a(sin theta-theta cos theta)

Find (dy)/(dx) if x=cos theta - cos 2 theta and" "y = sin theta - sin 2theta

Find (dy)/(dx) if x=cos theta - cos 2 theta and" "y = sin theta - sin 2theta

Find (dy)/(dx) if x=cos theta - cos 2 theta and" "y = sin theta - sin 2theta

Find (dy)/(dx) if x=cos theta - cos 2 theta and" "y = sin theta - sin 2theta

Find (dy)/(dx) : x=2 cos theta- cos^(2) theta and y=2 sin theta- sin 2theta Show that (dy)/(dx)= -1 " when " theta = (pi)/(2)

Find (dy)/(dx) if x= 3 cos theta - cos 2theta and y= sin theta - sin 2theta.