An electric bulb of volume 250cc was sealed during manufacturing at a pressure of `10^(-3)`mm of mercury at `27^(@)`C. Compute the number of air molecules contained in the bulb.Avogadro constant `=6xx10^(23)mol^(-1),` density of mercury`=13600kgm^(-3)and g=10ms^(-2)`.

Explanation

To solve the problem, we need to find the number of air molecules contained in a sealed electric bulb with given parameters. We will use the Ideal Gas Law and the provided data to calculate the number of molecules.

### Step-by-Step Solution:

1. **Identify Given Data:**
- Volume of the bulb, \( V = 250 \, \text{cc} = 250 \times 10^{-6} \, \text{m}^3 \)
- Temperature, \( T = 27^\circ C = 27 + 273 = 300 \, \text{K} \)
- Pressure, \( P = 10^{-3} \, \text{mm of Hg} \)
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