Buses start from a bus terminal with a speed of 40 km/hr, at intervals of 5 minutes What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 4 minutes

Explanation

Here, distance travelled by the bus in `5` minutes will be equal to the sum of the distance covered by the bus and the man in `4` minutes.

Let speed of the man is `x` km/h.
Then,

`40**5/60 = 40**4/60+x**4/60`

`=>10/3 = 8/3+x/15`

`=>2/3 = x/15`

`=>x = 10`

So, the speed of the man is `10` km/h.