Two moles of HI were heated in a sealed tube at `440^@ C` till the equilibrium was reached. HI was found to be 22% decomposed.The equilibrium constant for disssociation is :

HI heated in a sealed tube at 440^@C till the equilibrium was reached. HI was found to be 22% decomposed. The equilibrium constant for dissociation is:

HI was heated in a sealed tube at 400^(@)C till the equilibrium was reached. HI was found to be 22% decomposed. The equilibrium constant for dissociation is

HI was heated in a sealed tube at 400^(@)C till the equilibrium was reached. HI was found to be 22% decomposed. The equilibrium constant for dissociation is

HI was heated in a sealed tube at 440^Oc till the equiibrium was reached. HI was found to be 22% decomposed. Calculate the equilibrium constant for dissociation.

HI was heated in a sealed tube at 440^(@) C till the equilibrium was reached. HI was found to be 22% decomposed. The equilibrium constant for the dissociation of HI is [2HI hArr H_(2) + I_(2) ]

HI was heated in a sealed tube at 400^(@)C till the equilibrium was reached. HI was found to be 22% decomposed. The equilibrium for decomposition is :

Two moles of HI were heated in a scaled tube at 440^@C until the equilibrium was reached. HI was found to be 22% dissociated. Calculate equilibrium constant for the reaction 2HI(g) rarr H_2(g) + I_2(g) .

2 mol of HI were heated in a sealed tube at 440^(@)C until the equilibrium was reched. HI was found to be 22% dissociated. Calculate the equilibrium constant for the reaction 2HI(g)hArr H_(2)(g)+I_(2)(g) .