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(1) sin A = COS DU tan A=cot B Hs 15g 1 ...

(1) sin A = COS DU tan A=cot B Hs 15g 1 A+B =90°

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(tan A) / (1-cot A) + (cot A) / (1-tan A) = 1 + tan A + cot A = 1 + sec A cos ecA (1 + cos theta + sin theta) / (1 + cos theta-sin theta) = (1 + sin theta) / (cos theta)

if tan A=cot B then prove that A+B=90^(@)