Show that if a rod held at angle `theta` to the horizontal and released, its lower end will not slip if the friction coefficient between rod and ground is greater than `(3sinthetacostheta)/(1+3sin^(2)theta)`

Solve 1+sin^(2)theta=3sinthetacostheta

A uniform rod is held at an angle of 45^@ to the horizontal and released from rest as shown. The minimum coefficient of friction between plane and rod required so that the rod does not slip on the plane upon releases, will be

Solve the following equation: \ 3cos^2theta-2\ sqrt(3)sinthetacostheta-3sin^2theta=0

Solve the following equation: \ 3cos^2theta-2\ sqrt(3)sinthetacostheta-3sin^2theta=0

Solve the following equation: \ 3cos^2theta-2\ sqrt(3)sinthetacostheta-3sin^2theta=0

A uniform rod of length L rests against a smooth roller as shown in figure. Find the friction coefficient between the ground and the lower end if the minimum angle that rod can make with the horizontal is theta .

A uniform rod of length L rests against a smooth roller as shown in figure. Find the friction coefficient between the ground and the lower end if the minimum angle that rod can make with the horizontal is theta .

A uniform rod of length L rests against a smooth roller as shown in figure. Find the friction coefficient between the ground and the lower end if the minimum angle that rod can make with the horizontal is theta .

A uniform rod of length L rests against a smooth roller as shown in Fig. Find the friction coefficient between the ground and the lower end if the minimum angle that the rod can make with the horizontal is theta .

A rod is kept inclined at an angle theta with the horizontal A sleeve of mass m can slide on the rod. If the coefficient of friction between the rod and the sleeve is mu , for what values of horizontal acceleration a of the rod, towards left, the sleeve will not slide over the rod?