1
= -stanix + 5 tan's + C
In the above example only the part with partial fraction is substituted.
For the integral part. Now we discuss an example in which
Jointly used both the substitution method and the partial fraction method
dx
r + 3
gx + 3 / -
Poy
Example 15
d
Assume
5- cos-p-4 sinp
Suppose y = sinp
1
= -stanix + 5 tan's + C
In the above example only the part with partial fraction is substituted.
For the integral part. Now we discuss an example in which
Jointly used both the substitution method and the partial fraction method
dx
r + 3
gx + 3 / -
Poy
Example 15
d
Assume
5- cos-p-4 sinp
Suppose y = sinp
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