A rod of length 1.05 m having negligible mass is supported at its ends by two wires of steel (wire A) and aluminium (wire B) of equal lengths as shown in Fig. 9.15. The cross-sectional areas of wires A and B are 1.0 `"mm"^(2)` and 2.0 `"mm"^(2)`, respectively. At what point along the rod should a mass `m` be suspended in order to produce (a) equal stresses and (b) equal strains in both steel and aluminium wires.

A rod of length 1.05 m having negligible mass is supported at its ends by two wires of steel (wire A) and aluminium (wire B) of equal lengths as shown in figure. The cross-sectional areas of wires A and B are 1.0 mm^(2) and 2.0 mm^(2), respectively. At what point along the rod should a mass m be suspended in order to produce (a) equal stresses and (b) equal strains in both steel and aluminium wires.

A rod of length 1.05 m having negliaible mass is supported at its ends by two wires of steel (wire A) and aluminium (wire B) of equal lengths as shown in fig. The cross-sectional area of wire A and B are 1 mm^(2) and 2 mm^(2) , respectively . At what point along the rod should a mass m be suspended in order to produce (a) equal stresses and (b) equal strains in both steel and aluminium wires. Given, Y_(steel) = 2 xx 10^(11) Nm^(-2) and Y-(alumi n i um) = 7.0 xx 10^(10)N^(-2)

A rod of length 1.05 m having negliaible mass is supported at its ends by two wires of steel (wire A) and aluminium (wire B) of equal lengths as shown in fig. The cross-sectional area of wire A and B are 1 mm^(2) and 2 mm^(2) , respectively . At what point along the rod should a mass m be suspended in order to produce (a) equal stresses and (b) equal strains in both steel and aluminium wires. Given, Y_(steel) = 2 xx 10^(11) Nm^(-2) and Y-(alumi n i um) = 7.0 xx 10^(10)N^(-2)

A rod of length 1.05 m having negliaible mass is supported at its ends by two wires of steel (wire A) and aluminium (wire B) of equal lengths as shown in fig. The cross-sectional area of wire A and B are 1 mm^(2) and 2 mm^(2) , respectively . At what point along the rod should a mass m be suspended in order to produce (a) equal stresses and (b) equal strains in both steel and aluminium wires. Given, Y_(steel) = 2 xx 10^(11) Nm^(-2) and Y-(alumi n i um) = 7.0 xx 10^(10)N^(-2)

A rod of length 1.05 m having negligible mass is supported at its ends by two wires of steel (wire A) and aluminium (wire B) of equal lengths as shown in Fig. 9.15. The cross-sectional areas of wires A and B are 1.0 mm^2 and 2.0 mm^2 , respectively. At what point along the rod should a mass m be suspended in order to produce equal strains in both steel and aluminium wires.:

A rod of length 1.05 m having negligible mass is supported at its ends by two wires of steel (wire A) and aluminium (wire B) of equal length as shown in the figure The cross sectional area of wires A and B are 1.0 mm^2 and 2.0 mm^2 , respectivley. AT wat point along the rod should a mass m be suspended in order to produce .equal stresses.

A rod PQ of length 1.05m having negligible mass is supported at its ends by two wires one of stell (wire A ), and the other of aluminium (wire B ) of equal lengths as shown in fig. The cross-sectional areas of wires A and B are 1.0mm^(2) and 2.0mm^(2) respectively. At what point along the rod a load W be suspended in order to produce (a) equal stress, (b) equal strains in both steel an aluminium. (Y_("steel") = 200 GPa, Y_("aluminium") = 70 GPa)

A rod of length 1.05 m having negligible mass is supported at its ends by two wires of steel (wire A) and aluminium (wire B) of equal length as shown in the figureThe cross sectional area of wires A and B are 1.0 mm^2 and 2.0 mm^2 , respectivley. AT wat point along the rod should a mass m be suspended in order to produce equal strains in both steel and aluminium wires?

A rod of length l and negligible mass is suspended at its two ends by two wires of steel (wire A ) and aluminium (wire B) of equal length (shown in the figure) The cross-sectional areas of wires A and B are 1.0 mm^2 and 2.0 mm^2 , respectively. (Y_(AL) = 70 xx 10^9 N m^-2 and y _(steel) = 200 xx 10^9 N m^-2)