In the figure, M is the mid point of `CA. DM` produced meet BA at B N also `AN=AM`, Prove that `(BD)/(BN)= (DC)/(CM)`.

In the given figure, M is the mid-point of both AC and BD. Then

In Figure O is the mid-point of aB and CD. Prove tat AC=BD and AC||BD.

M is a point on the side BC of a parallelogram ABCD. DM when produced meets AB produced at N. Prove that (i) (DM)/(MN)=(DC)/(BN)" " (ii) (DN)/(DM)=(AN)/(DC)

in figure,M is the mid-point of AB and N is the mid-point of BC(1) if AB=BC, prove that AM=NC

in figure,M is the mid-point of AB and N is the mid-point of BC(1) if AB=BC, prove that AM=NC

In the fig. ABCD is a square M is the mid point and PQ bot CM meets AD at and CB produced prove that PA=BQ?

In the give figure AB = BC, M is the mid point of AB and N is the mid point of BC, Show that AM = NC

In the figure ABCD is a llgm and E is the mid point of BC. Also DE and AB when produced meet at F then

In figure,P is the mid-point of BC, Q is the mid-point of AP, such that BQ produced meets AC at R .Prove that 3RA=CA