Calculate the amount of `(NH_(4))_(2)SO_(4)` in grams which must be added to `500ml` of `0.2MNH_(3)` to give a solution of `pH=9.3` .Given `pK_(b)` for `NH_(3)=4.7`.

Calculate the amount of (NH_(4))_(2)SO_(4) in grams which must be added to 500 ml of 0.2 M NH_(3) to yield a solution of pH=9 , K_(b) for NH_(3)=2xx10^(-5)

What will be the amount of (NH_(4))_(2)SO_(4) (in g) which must be added to 500 mL of 0.2 M NH_(4)OH to yield a solution of pH 9.35? ["Given," pK_(a)"of "NH_(4)^(+)=9.26,pK_(b)NH_(4)OH=14-pK_(a)(NH_(4)^(+))]

What will be the amount of (NH_(4))_(2)SO_(4) (in g) which must be added to 500 mL of 0.2 M NH_(4)OH to yield a solution of pH 9.35? ["Given," pK_(a)"of "NH_(4)^(+)=9.26,pK_(b)NH_(4)OH=14-pK_(a)(NH_(4)^(+))]

Calculate the amount of (NH_4)^2SO_4 in g which must be added to 500 mL of 0.2 MNH_3 to yield a solution of pH=9.35, K_b for NH_3 = 1.78xx10^-5

Calculate the weight of (NH_(4))_(2)SO_(4) which must be added to 500mL of 0.2M NH_(3) to yield a solution of pH = 9.35. K_(a) for NH_(3) = 1.78 xx 10^(-5) .