A wire of resistance `4 Omega` is stretched to twice its original length. The resistance of stretched wire would be

A resistance 10 Omega is stretched to twice its original length . The resistance of the stretched wire is

A resistance 10 Omega is stretched to twice its original length . The resistance of half of the stretched wire is

A wire of resistance (10 Omega) is stretched to twice its original length. The resistance of half of the streached wire is

A wire of resistance R is stretched to three times its original length. The new resistance is

A wire of resistance 4 Omega is stretched to twice its original length. In the process of stretching, its area of cross-section gets halved. Now, the resistance of the wire is

A wire of resistance 4 Omega is stretched to twice its original length. In the process of stretching, its area of cross-section gets halved. Now, the resistance of the wire is

A wire of resistance 4 Omega is stretched to four times of its original length resistance of wire now becomes

If a wire of resistance R is stretched to twice its original length, the new resistance of the wire will be:

A wire of resistance 1 Omega is stretched to double its length. Then its resistance becomes