The image of the point `(-1,3,4)` in the plane `x-2y=0` is a. `(-(17)/3,-(19)/3,4)` b. `(15 ,11 ,4)` c. `(-(17)/3,-(19)/3,1)` d. `(9/5,(-13)/5,4)`

the image of the point (-1,3,4) in the plane x-2y=0 a. (-(17)/(3),(19)/(3),4) b. (15,11,4) c. (-(17)/(3),(19)/(3),1) d. ((9)/(5),-(13)/(5),4)

the image of the point (-1,3,4) in the plane x-2y=0 a. (-(17)/(3),(19)/(3),4) b.(15,11,4) c. (-(17)/(3),(19)/(3),1) d. ((9)/(5),-(13)/(5),4)

The image of the point (1, 3, 4) in the plane 2x-y+z+3=0 is (3,\ 5,\ 2) b. (-3,5,\ 2) c. (3,\ 5,\ -2) d. (3,\ -5,\ 2)

The image of the point (1, 3, 4) in the plane 2x-y+z+3=0 is (3,\ 5,\ 2) b. (-3,5,\ 2) c. (3,\ 5,\ -2) d. (3,\ -5,\ 2)

Foot of the perpendicular drawn from the origin to the plane 2x - 3y + 4z = 29 is a) (5,-1,4) b) (7,-1,3) c) (5,-2,3) d) (2,-3,4)

Let P=0 be the equation of a plane passing through the line of intersection of the planes 2x-y=0a n d3z-y=0 and perpendicular to the plane 4x+5y-3z=8. Then the points which lie on the plane P=0 is/are a. (0,9,17) b. (1//7,2,1//9) c. (1,3,-4) d. (1//2,1,1//3)

The points (3,-2,-1),(-1,1,2),(2,3,-4) and (4,5,lamda) are coplanar when lamda= (A) 0 (B) (-146)/17 (C) 1 (D) (-17)/9

The points (3,-2,-1),(-1,1,2),(2,3,-4) and (4,5,lamda) are coplanar when lamda= (A) 0 (B) (-146)/17 (C) 1 (D) (-17)/9

The point of intersection of tangent to the curve y=x^4 at (1,1) with the normal to the same curve at (-1,1) is (A) ((17)/(15),(13)/(15)) (B) (7/5,3/5) (C) ((17)/(15),(23)/(15)) (D) does not exist