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If sintheta+sin2theta+sin3theta=sinalpha...

If `sintheta+sin2theta+sin3theta=sinalpha` and `costheta+cos2theta+cos3theta=cosalpha` , then `theta` is equal to

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Prove that (sin theta+ sin 2theta + sin 3 theta)/(costheta+cos2theta+cos3theta)=tan 2 theta

(sintheta+sin2theta)/(1+costheta+cos2theta) =

(sintheta+sin2theta)/(1+costheta+cos2theta)