Find the time required for a cylindrical tank of radius `r` and height `H` to empty through a round hole of area `a` at the bottom. The flow through the hole is according to the law `v(t)=ksqrt(2gh(t))` , where `v(t)` and `h(t)` , are respectively, the velocity of flow through the hole and the height of the water level above the hole at time `t ,` and `g` is the acceleration due to gravity.

A hemi-spherical tank of radius 2 m is initially full of water and has an outlet of 12c m^2 cross-sectional area at the bottom. The outlet is opened at some instant. The flow through the outlet is according to the law v(t)=0.6sqrt(2gh(t)), where v(t) and h(t) are, respectively, the velocity of the flow through the outlet and the height of water level above the outlet and the height of water level above the outlet at time t , and g is the acceleration due to gravity. Find the time it takes to empty the tank.

A hemi-spherical tank of radius 2 m is initially full of water and has an outlet of 12c m^2 cross-sectional area at the bottom. The outlet is opened at some instant. The flow through the outlet is according to the law v(t)=0.6sqrt(2gh(t)), where v(t) and h(t) are, respectively, the velocity of the flow through the outlet and the height of water level above the outlet and the height of water level above the outlet at time t , and g is the acceleration due to gravity. Find the time it takes to empty the tank.

A hemi-spherical tank of radius 2 m is initially full of water and has an outlet of 12c m^2 cross-sectional area at the bottom. The outlet is opened at some instant. The flow through the outlet is according to the law v(t)=0.6sqrt(2gh(t)), where v(t) and h(t) are, respectively, the velocity of the flow through the outlet and the height of water level above the outlet and the height of water level above the outlet at time t , and g is the acceleration due to gravity. Find the time it takes to empty the tank.

A hemi-spherical tank of radius 2 m is initially full of water and has an outlet of 12c m^2 cross-sectional area at the bottom. The outlet is opened at some instant. The flow through the outlet is according to the law v(t)=sqrt(0. 62gh(t)), where v(t) and h(t) are, respectively, the velocity of the flow through the outlet and the height of water level above the outlet and the height of water level above the outlet at time t , and g is the acceleration due to gravity. Find the time it takes to empty the tank.

Find the time required for a cylindrical tank of radius 2.5m and height 3m to empty through a round hole of 2.5cm with a velocity 2.5sqrt(h)m/s,h being the depth of the water in the tank.

Find the time required for a cylindrical tank of radius 2.5 m and height 3 m to empty through a round hole of 2.5 cm with a velocity 2. 5sqrt(h) m/s, h being the depth of the water in the tank.

Find the time required for a cylindrical tank of radius 2.5 m and height 3 m to empty through a round hole of 2.5 cm with a velocity 2. 5sqrt(h) m/s, h being the depth of the water in the tank.

Find the time required for a cylindrical tank of radius 2.5 m and height 3 m to empty through a round hole of radius 2.5 cm with a velocity 2. 5sqrt(h) m/s, h being the depth of the water in the tank.

Find the time required for a cylindrical tank of radius 2.5 m and height 3 m to empty through a round hole of radius 2.5 cm with a velocity 2. 5sqrt(h) m/s, h being the depth of the water in the tank.