A mass of 1 kg is just able to slide down the slope of an inclined rough surface when the angle of inclination is `60^(@)` The minima force necessary to pull the mass up the inclined plane is: `(g=10 m//s^(2))`

A mass of 1 kg is just able to slide down the slope of a rough inclined surface when the angle of inclination is 60°. What is the minimum force necessary to pull the mass up the inclined plane? (g =10m//s^2 )

A mass of 0.5 kg is just able to slide down the slope of an inclined rough surface when the angle of inclination is 60^(@) . The minimum force necessary to pull the mass up the incline along the line of greatest slope is : (Take g=10m//s^(2) )

A body of mass 10 kg is lying on a rough inclined plane of inclination 37^(@) and mu = 1//2 , the minimum force required to pull the body up the plane is

A block of mass 5 kg is at rest on a rough inclined surface. If angle of inclination of plane is 60^(@) , then force applied by it on block is

A block of mass 5 kg is at rest on a rough inclined surface. If angle of inclination of plane is 60^(@) , then force applied by it on block is

A block of mass 10 kg is placed on an inclined plane when the angle of inclination is 30^(@) . The block just begins to slide down the plane. The force of static friction is

A block of mass 5 kg and surface area 2m^(2) just begins to slide down an inclined plane when the angle on inclination is 30^(@) . Keeping mass same, the surface area of the block is doubled. The angle is which this starts sliding down is

A block of mass 5 kg and surface area 2m^(2) just begins to slide down an inclined plane when the angle on inclination is 30^(@) . Keeping mass same, the surface area of the block is doubled. The angle is which this starts sliding down is