25*(2n+7)<(n+3)^(2)

Find n if. (((2n) !) / (7 !(2n - 7) !)) / ((n !) / (4 !(n - 4) !)) = 24 / 1

If n is a natural numbers then 25^(2n)-9^(2n) is always divisible by

Simplify : frac(5^n xx 25^(2n-2))(5^(3n-2) xx 10^-1)

lim_ (n rarr oo) (2.5 ^ (n + 1) -3.7 ^ (n + 1)) / (2.5 ^ (n) + 3.7 ^ (n)) =

By method of induction prove that 1.3 + 2.5 + 3.7 +...+ n (2n + 1) = n/6 (n + 1) (4n + 5) for all n in N

The value of (5.(25)^(n+1) + 25.(5)^(2n-1))/(25.(5)^(2n) -105(25)^(n-1)) is :

if 25C_(n+5)=25C_(2n-1) then sum of all values of n is:

Find the value of 2.5^2 + 2 ( 2.5 ) ( 7.5 ) + 7.5^2

Simplify the following: (3^(n)x9^(n+1))/(3^(n-1)x9^(n-1)) (ii) (5x25^(n+1)-25x5^(2n))/(5x5^(2n+3)-(25)^(n+1))