Calculate the `[OH^(-)]` in 0.1 M aqueous solution of NaOCN `(K_(b)` for `OCN^(-)=10^(-10))`:

Calculate the [OH^(-)] in 0.01M aqueous solution of NaOCN(K_(b) for OCN^(-)=10^(-10)) :

Calculate the [OH^(-)] in 0.01M aqueous solution of NaOCN(K_(b) for OCN^(-)=10^(-10)) :

Calculate the [OH^(-)] in 0.01M aqueous solution of NaOCN(K_(b) for OCN^(-)=10^(-10)) : (a) 10^(-6) M (b) 10^(-7) M (c) 10^(-8) M (d)None of these

Calculate the [OH^-] in 0.01 M aqueous solution of NaOCN (K_b for OCN^-)=10^-10)

Calculate the percentage hydrolysis in 0.003M aqueous solution of NaOCN. (K_(a)for HOCN=3.33xx10^(-4))

Calculate [OH^(-)] in 0.20M solution of NH_(3) , if K_(b) for NH_(3) is 1.8xx10^(-5) .

a. Calculate the percentage hydrolysis of 0.003M aqueous solution of NaOH. K_(a) for HOCN = 3.3 xx 10^(-4) . b. What is the pH and [overset(Theta)OH] of 0.02M aqueous solution of sodium butyrate. (K_(a) = 2.0 xx 10^(-5)) .