A second pendulum is moved to moon where acceleration dur to gravity is 1/6 times that of the earth, the length of the second pendulum on moon would be

If a Seconds pendulum is moved to a planet where acceleration due to gravity is 4 times, the length of the second's pendulum on the planet should be made

If a Seconds pendulum is moved to a planet where acceleration due to gravity is 4 times, the length of the second's pendulum on the planet should be made

A second's pendulum on the earth is taken to the moon, where acceleration due to gravity is nearly 1/6 th that on the earth. If it is to act as second's pendulum there too on the moon, its length should be

If the acceleration due to gravity on moon is one-sixth of that on the earth, what will be the length of a second pendulum there ? Take g = 9.8 ms^-2

The acceleration due to gravity on the moon is (1)/(6) th the acceleration due to gravity on the surface of the earth. If the length of a second's pendulum is 1 m on the surface of the earth, then its length on the surface of the moon will be