int_(x^(2)/46)^(x^(2))(sin x*sin sqrt(theta))/(1+cos^(2)sqrt(theta))*d theta

If f(x)=int_((x^(2))/(16))^(x^(2))(sin x sin sqrt(theta))/(1+cos^(2)sqrt(theta))d theta, then find the value of f'((pi)/(2))^((16)/(16))

If y(x)=int_((pi^(2))/(16))^(x^(2))(cos x cos sqrt(theta))/(1+sin^(2)sqrt(theta))d theta then find y'(pi)

If y(x)=int_((pi^(2))/(16))^(x^(2))(cos x cos sqrt(theta))/(1+sin^(2)sqrt(theta)), then f in d(dy)/(dx)atx=pi

If y(x)=int_(pi^2/16)^(x^2)(cosxcossqrt(theta))/(1+sin^2sqrt(theta)),then (dy)/(dx) at x=pidot is

int(sin^(3)theta)/(sqrt(cos theta))d theta

int(sin theta+cos theta)/(sqrt(1+sin2 theta))d theta

int (sin theta + cos theta)/(sqrt(sin 2 theta) ) d theta =

int(sqrt(cos2 theta))/(sin theta)d theta=

If f(x)=int_(0)^((pi)/(2))(ln(1+x sin^(2)theta))/(sin^(2)theta)d theta,x>=0 then :